\(a^2 + b^2 = c^2\)
\(E = mc^2\)
\(\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}\)
\(e^{i\pi} + 1 = 0\)
\(\int_0^\infty e^{-x^2} dx = \frac{\sqrt{\pi}}{2}\)
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